Question

A length change - 0.18 m will occur for an object that is L- 80 m long, If the coeffcient of thermal expansion is12 x 106/C and if the original temperature is 83 C, find the final temperature.

Answer 1

The final temperature is 270.5°C

Step-by-step explanation:

Given that,

Change length = 0.18 m

Length = 80 m

Coefficient of thermal expansion
`\alpha=12*10^(-6)\ C^(\circ)`

Temperature = 83°C

We need to calculate the final temperature

Using formula thermal expansion

`\delta l=l\alpha*\delta t`

Where,
`\Delta l` =change in length

`\Delta t` = change in temperature

`\alpha` = coefficient of thermal expansion

Put the value into the formula

`0.18=80*12\tmes10^(6)*(T_(f)-T_(i))`

`T_(f)-83=(0.18)/(80*12*10^(-6))`

`T_(f)=187.5+83=270.5^(\circ) C`

Hence, The final temperature is 270.5°C