Question

An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the magnitude of the electric flux througha rectangular area of 1.65 m2 in the xy-plane. N m2/C

Answer 1

The magnitude of the electric flux is
`3.53\ N-m^2/C`

Step-by-step explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

Area
`A= 1.65 m^2`

We need to calculate the flux

Using formula of the magnetic flux

`\phi=E\cdot A`

`\phi = EA\cos\theta`

Where,

A = area

E = electric field

Put the value into the formula

`\phi=2.35*1.65*\cos 25^(\circ)`

`\phi=2.35*1.65*0.91`

`\phi=3.53\ N-m^2/C`

Hence, The magnitude of the electric flux is
`3.53\ N-m^2/C`