Answer:
22.47 %
Step-by-step explanation:
v 1 = 328 m/s, v 2 = 363 m/s
We know that the velocity of a wave in a stretch string is directly proportional to the square root of the tension in the string.
Percentage increase in the tension
= \left ( \frac{1}{0.8165}-1 \right )\times 100
= 22.47 %