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Bryan hits a golf ball whose path is given by the function f(d) = -0.01d2 + 3d, where d is the distance the ball travelled in feet and f(d) is the height of the ball. The height of the golf ball when it was hit was feet and the ball reached a maximum height of feet.

User Richflow
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Bryan hits a golf ball whose path is given by the function f(d) = -0.01d2 + 3d, where d is the distance the ball travelled in feet and f(d) is the height of the ball. The height of the golf ball when it was hit was feet and the ball reached a maximum height of feet.

User Aab
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Answer:

  • 0 ft
  • 225 ft

Explanation:

h(0) = -.01·0² +3·0 = 0 . . . . . the height when the ball was hit

The function can be factored as ...

f(d) = -0.01d(d -300)

This has zeros at d=0 and d=300, so the maximum will be halfway between, at d=150.

f(150) = -0.01·150(150 -300) = -1.5(-150) = 225

The height of the ball when hit was 0 feet, and the ball reached a maximum height of 225 feet.

Bryan hits a golf ball whose path is given by the function f(d) = -0.01d2 + 3d, where-example-1
User Srikanth Kandalam
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