Question

A vertical straight wire carrying an upward 24-A current exerts an attractive force per unit length of 88 X 104N/m on a second parallel wire 7.0 cm away. What current (magnitude and direction) flows in the second wire?

Answer 1

The current flows in the second wire is
`1.3*10^(10)\ A`

Step-by-step explanation:

Given that,

Upward current = 24 A

Force per unit length
`(F)/(l) =88*10^(4)\ N/m`

Distance = 7.0 cm

We need to calculate the current in second wire

Using formula of magnetic force

`F=ILB`

`(F)/(l)=(\mu I_(1)I_(2))/(2\pi r)`

Where,

`(F)/(l)`=force per unit length

I₁= current in first wire

I₂=current in second wire

r = distance between the wires

Put the value into the formula

`88*10^(4)=(4\pi*10^(-7)*24* I_(2))/(2\pi *7*10^(-2))`

`I_(2)=(88*10^(4)*7*10^(-2))/(2**10^(-7)*24)`

`I_(2)=1.3*10^(10)\ A`

Hence, The current flows in the second wire is
`1.3*10^(10)\ A`