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A vertical straight wire carrying an upward 24-A current exerts an attractive force per unit length of 88 X 104N/m on a second parallel wire 7.0 cm away. What current (magnitude and direction) flows in the second wire?

User Zonble
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1 Answer

6 votes

Answer:

The current flows in the second wire is
1.3*10^(10)\ A

Step-by-step explanation:

Given that,

Upward current = 24 A

Force per unit length
(F)/(l) =88*10^(4)\ N/m

Distance = 7.0 cm

We need to calculate the current in second wire

Using formula of magnetic force


F=ILB


(F)/(l)=(\mu I_(1)I_(2))/(2\pi r)

Where,


(F)/(l)=force per unit length

I₁= current in first wire

I₂=current in second wire

r = distance between the wires

Put the value into the formula


88*10^(4)=(4\pi*10^(-7)*24* I_(2))/(2\pi *7*10^(-2))


I_(2)=(88*10^(4)*7*10^(-2))/(2**10^(-7)*24)


I_(2)=1.3*10^(10)\ A

Hence, The current flows in the second wire is
1.3*10^(10)\ A

User Slcott
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