Question

What is the molarity of NaOH solution of 112 g of NaOH dissolved in 0.750 L of solvent

Answer 1

Answer : The molarity of NaOH is, 3.733 mole/L

Explanation : Given,

Mass of NaOH = 112 g

Molar mass of NaOH = 40 g/mole

Volume of solution = 0.750 L

Molarity : It is defined as the number of moles of solute present in one liter of solution.

In this question, the solute is NaOH.

Formula used :

`Molarity=(w_b)/(M_b* V)`

where,

`w_b` = mass of solute NaOH = 112 g

`M_b` = molar mass of solute NaOH = 40 g/mole

V = volume of solution = 0.750 L

Now put all the given values in the above formula, we get the molarity of the solution.

`Molarity=(112g)/(40g/mole* 0.750L)=3.733mole/L`

Therefore, the molarity of NaOH is, 3.733 mole/L

Answer 2

0.373M

Step-by-step explanation:

Given parameters:

Mass of NaOH given = 112g

Volume of solvent = 0.75L

Solution:

1....To solve this problem, we first find the number of moles of the solute using the expression below:

Number of moles = mass/molar mass

Solving:

Molar mass of NaOH

Atomic mass of Na = 23g

Atomic mass of O = 16g

Atomic mass of H = 1g

Molar mass = 23 + 16 + 1 = 40g/mol

Number of moles = 112/40 = 2.8mol

2..... From the number of moles of solute, we then evaluate the molarity of the solution that would be produced using the expression below:

Molarity = number of moles/Volume

Molarity = 2.8/0.75 = 0.373M