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If a display has a dynamic range of 20 dB and the smallest voltage it can handle is 200 mV, then the largest voltage it can handle is_________V.

a. 20

b. 2.0

c. 0.2

d. 0.02

User Shy
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1 Answer

7 votes

Answer:

The largest voltage is 0.02 V.

(d) is correct option.

Step-by-step explanation:

Given that,

Range = 20 dB

Smallest voltage = 200 mV

We need to calculate the largest voltage

Using formula of voltage gain


G_(dB)=10 log_(10)((V_(out)^2)/(V_(in)^(2)))


20 =10 log_(10)((V_(out)^2)/(V_(in)^(2)))


2=log_(10)((V_(out)^2)/(V_(in)^(2)))


10^2=(V_(out)^2)/(V_(in)^(2))


(V_(out))/(V_(in)^)=10


V_(in)=(V_(out))/(10)


V_(in)=(200)/(10)


V_(in)=20\ mV


V_(in)=0.02\ V

Hence, The largest voltage is 0.02 V.

User Constt
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