Question

A 3500-kg statue is placed on top of a cylindrical concrete (Y = 2.3 times 10^10 N/m^2) stand. The stand has a cross-sectional area of 7.3 times 10^-2 m^2 and a height of 1.8m. By how much the statue compress the stand?

Answer 1

The statue compress the stand by 3.68 x 10⁻⁵ m.

Step-by-step explanation:

Change in length

`\Delta L=(PL)/(AY)`

Load, P = 3500 x 9.81 = 34335 N

Young's modulus, Y = 2.3 x 10¹⁰ N/m²

Area, A = 7.3 x 10⁻² m²

Length, L = 1.8 m

Substituting

`\Delta L=(PL)/(AE)=(34335* 1.8)/(7.3* 10^(-2)* 2.3* 10^(10))=3.68* 10^(-5)m`

The statue compress the stand by 3.68 x 10⁻⁵ m.