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1 vote
A pet store owner set the price of a bag of cat food at 50% above the cost. When it did not sell, the price was reduced by 20%, to $12.00. What was the original cost?

User Tophers
by
7.9k points

2 Answers

1 vote

Answer:

60

Explanation:

User LacOniC
by
8.3k points
6 votes

Answer:

$10.

Explanation:

Let x represent the original cost of bag of cat food.

We have been given that a pet store owner set the price of a bag of cat food at 50% above the cost. So the cost of cat food would be x plus 50% of x.


x+(50)/(100)*x\rightarrow x+0.5x=1.5x

We are further told that the price was reduced by 20%, when it did not sell. So price of cat food after reduction would be
1.5x minus 20 percent of
1.5x.


1.5x-((20)/(100)* 1.5x)


1.5x-(0.20* 1.5x)


1.5x-(0.3x)


1.2x

Since price after reduction was $12, so we will equate
1.2x with 12 as:


1.2x=12


(1.2x)/(1.2)=(12)/(1.2)


x=10

Therefore, the original cost of cat food was $10.

User DarkMath
by
8.0k points

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