Question

A certain gasoline engine has an efficiency of 35.3%. What would the hot reservoir temperature be for a Carnot engine having that efficiency, if it operates with a cold reservoir temperature of 160°C? (°C)

Answer 1

The temperature of hot reservoir is 669.24 K.

Step-by-step explanation:

It is given that,

Efficiency of gasoline engine,
`\eta=35.3\%=0.353`

Temperature of cold reservoir,
`T_C=160^(\circ)C=433\ K`

We need to find the temperature of hot reservoir. The efficiency of Carnot engine is given by :

`\eta=1-(T_C)/(T_H)`

`T_H=(T_C)/(1-\eta)`

`T_H=(433)/(1-0.353)`

`T_H=669.24\ K`

So, the temperature of hot reservoir is 669.24 K. Hence, this is the required solution.