44.3k views
0 votes
A certain gasoline engine has an efficiency of 35.3%. What would the hot reservoir temperature be for a Carnot engine having that efficiency, if it operates with a cold reservoir temperature of 160°C? (°C)

1 Answer

3 votes

Answer:

The temperature of hot reservoir is 669.24 K.

Step-by-step explanation:

It is given that,

Efficiency of gasoline engine,
\eta=35.3\%=0.353

Temperature of cold reservoir,
T_C=160^(\circ)C=433\ K

We need to find the temperature of hot reservoir. The efficiency of Carnot engine is given by :


\eta=1-(T_C)/(T_H)


T_H=(T_C)/(1-\eta)


T_H=(433)/(1-0.353)


T_H=669.24\ K

So, the temperature of hot reservoir is 669.24 K. Hence, this is the required solution.

User Knio
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.