Question

How many iron atoms are in 0.32 mol of Fe2031? 3.9x 1023 jron atoms O 3.9 iron atoms O 6.02 x 1023 iron atoms 1.9 x 1023 iron atoms O 11x 10-24 iron atoms

Answer 1

Answer:
`3.9* 10^(23)` iron atoms

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

`1 molecule of [tex]Fe_2O_3` contains= 2 atoms of iron

`1 mole of [tex]Fe_2O_3` contains=
`2* 6.023* 10^(23)=12.05* 10^(23)` atoms of iron

thus 0.32 moles of
`Fe_2O_3` contains=
`(12.05* 10^(23))/(1)* 0.32=3.9* 10^(23)` atoms of iron

Thus the sample would have
`3.9* 10^(23)` iron atoms.