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What is the general form of the equation of a circle with its center at (-2,1) and passing through (-4,1)

User Seumasmac
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1 Answer

4 votes

Answer:

(x + 2)^2 + (y - 1)^2 = 2^2

Explanation:

The equation of this circle is

(x + 2)^2 + (y - 1)^2 = r^2, and we are to determine the values of r^2 and r by substituting -4 for x and 1 for y:

(-4 + 2)^2 + (1 - 1)^2 = r^2, or:

(-2)^2 = r^2, or

4 = r^2

Then r = 2.

The desired equation is:

(x + 2)^2 + (y - 1)^2 = 2^2

User Amdmax
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