Question

Find the first five terms of the sequence in which a(1) = –10 and a(n) = 4a(n) – 1 + 7, if n ≥ 2.

options:

A –33, –125, –493, –1965, –7853

B 11, 15, 19, 23, 27

C 47, –10, –33, –125, –493

D –10, –33, –125, –493, –1965

Answer 1

hello : answer: A

Explanation:

a(1) = –10 and a(n) = 4a(n– 1) + 7, if n ≥ 2.

n=2 : a(2)=4a(1)+7 a(2) =4(-10)+7 = -33

n=3 : a(2)=4a(2)+7 a(3) =4(-33)+7 = -125

n=4 : a(2)=4a(3)+7 a(4) =4(-125)+7 = -493

n=5 : a(2)=4a(4)+7 a(5) =4(-493)+7 = -1965

n=6 : a(2)=4a(5)+7 a(6) =4(-1965)+7 = -7853

Answer 2

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