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Solve 7r+ 2 = 5(r – 4) ​

User Acj
by
7.1k points

2 Answers

3 votes

Multiply the bracket by 5

I used PEMDAS

P= parenthesis

E= exponents

M=multiplication

D= division

A= addition

S= subtraction

7r+2= 5(r-4)

7r+2= 5r-20

Move 5r to the left hand side . Positive 5r changes to negative 5r

7r-5r+2= 5r-5r-20

2r+2=- 20

2r+2-2= -20-2

Move positive 2 to the right hand side. Changes to negative -2

2r+2-2= -20-2

2r= -22

Divide by 2 for 2r and -22

2r/2= -22/2

r= -11

Answer is r= -11

User Yevhen Bobrov
by
7.9k points
4 votes

Answer:

r = (-11)

Explanation:

7r + 2 = 5(r – 4) ​

7r + 2 = 5r – 4 * 5

7r + 2 = 5r – 20

7r - 5r = -20 - 2

2r = -22

r = -22/2 = (-11)

User Rahat Khanna
by
7.7k points

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