Question

What are the solutions to the system of equations
{-x+y=4
{y+12=x^2+x

Answer 1

Explanation:

`y=4+x` ............................................ (1)

`y=x^2+x-12` ............................................ (2)

now equate both (1) and (2)

`4+x=x^2+x-12`

`=>x^2=16`

`x=-4,4`

now substitute the values of x ,

when
`x=-4` , y becomes 0

when
`x=4` , y becomes 8

so, solution set:

`(-4,0)` and
`(4,8)`