Question

At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 µT northward, and the electric field is about 100 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron in this environment, assuming the electron has an instantaneous velocity of 5.90 ✕ 106 m/s directed to the east in this environment.

Answer 1

`F_g = 8.9 * 10^(-30) N`

`F_e = 1.6 * 10^(-17) N`

`F_m = 4.72 * 10^(-17) N`

Step-by-step explanation:

For gravitational force we know that

F = mg

now we have

`m = 9.1 * 10^(-31) kg`

`F_g = (9.1 * 10^(-31))(9.8)`

`F_g = 8.9 * 10^(-30) N`

Now electrostatic force

`F = qE`

here we have

`F = (1.6 * 10^(-19))(100)`

`F = 1.6 * 10^(-17) N`

Now magnetic force on it is given by

`F_(m) = qvB`

`F_m = (1.6 * 10^(-19))(5.90 * 10^6)(50 * 10^(-6))`

`F_m = 4.72 * 10^(-17) N`