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1 vote
Find the image of (1,2) after a

reflection about x = 6 followed by a
reflection about x = 4.

1 Answer

4 votes

Answer:

(-3,2)

Explanation:

When the point P(x,y) is reflected in the line
x=k, the mapping is


P(x,y)\to P'(2k-x,y).

The image of (1,2) after a reflection about x = 6 is


(1,2)\to (2*6-1,2).


(1,2)\to (12-1,2).


(1,2)\to (11,2).

When the resulting point is again reflected in the line x=4, we obtain


(11,2)\to (2*4-11,2).


(11,2)\to (8-11,2).


(11,2)\to (-3,2).

Therefore the image of (1,2) after a

reflection about x = 6 followed by a

reflection about x = 4 is (-3,2)

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