Question

A line intersects the point (-8,-1)and has a slope of 1/4.what is the slope-intercept equation for this line?

Answer 1

`y = (1)/(4)x+1`

Step-by-step explanation

The slope-intercept equation of a straight line is of the form

`y = mx + b`

Where 'm' is the slope and 'b' is the y-intercept.

From the question we have slope to be

`m = (1)/(4)`

We substitute the slope into the slope-intercept equation and obtain:

`y = (1)/(4)x + b`

To find the value of 'b' we plug in the point (-8,-1) into our current equation.

`- 1= (1)/(4)( - 8)+ b`

`- 1= - 2+ b`

`- 1 + 2 = b`

`1 = b`

`b =1`

The complete equation is

`y = (1)/(4)x + 1`