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Determine the axis of symmetry for the function f(x)=-2(x+3)^2-5

User KZiovas
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2 Answers

5 votes

Answer:

B) x=-3 (Negative 3)

Explanation:

I took the math exam

User Adam Bethke
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5.2k points
3 votes

Answer:

x=-3

Explanation:

f(x)=-2(x+3)^2-5

The equation is in the form

f(x) = a(x-h)^2 -k

where (h,k) is the vertex

The h value is also the axis of symmetry

f(x)=-2(x--3)^2-5

The vertex is (-3,-5)

so the axis of symmetry is x=-3

User Limserhane
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5.0k points