Question

Calculate the frequency of photon 434E-9 and speed of light 3E8m/s

Answer 1

Frequency,
`f=6.91* 10^(14)\ Hz`

Step-by-step explanation:

It is given that,

Wavelength,
`\lambda=434* 10^(-9)\ m`

Speed of light,
`c=3* 10^8\ m/s`

The frequency of photon can be calculated using following relation as :

`c=f* \lambda`

`f=(c)/(\lambda)`

`f=(3* 10^8\ m/s)/(434* 10^(-9))`

`f=6.91* 10^(14)\ Hz`

So, the frequency of the photon is
`f=6.91* 10^(14)\ Hz`. Hence, this is the required solution.

Answer 2

f = 6.912 E14 Hz

Step-by-step explanation:

The speed of the wave is defined as

speed = wavelength*frequency

the frequency of the photon is defined as

f = speed / wavelength

f = 3 E8 m/s / 434 E-9 m

f = 6.912 E14 Hz