Question

Which shows one way to determine the factors 4x^3+x^2-8x-2 by grouping

Answer 1

Explanation:

Note that the first two terms have the factor 4x + 1 and that this is also a factor of the last two terms. Thus, 4x^3+x^2-8x-2 = (4x + 1)(x^2 - 2). This last result is further factorable: (4x + 1)(x - √2)(x + √2).

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