Answer:
The mean absolute deviation is approximately is 11.43.
Explanation:
The means absolute deviations is define by:
![D_(x) =(\sum |x_(i)-x| )/(N)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ynhlukxs64tat8ypwlf9m02kmljn62nes.png)
From the formula, we observe that we need to find the mean, and then find the different between that mean and each element. Then, we have to sum all those differences and divide this by the total number of elements.
So, the mean is
![x=(\sum x_(i) )/(N)\\ x=(40+55+35+60+20+50+55)/(7)=45](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qb26z349g2mqiaz8val6mtjaepil23wwzs.png)
Now, each difference would be
![40-45=-5\\55-45=10\\35-45=-10\\60-45=15\\20-45=-25\\50-45=5\\55-45=10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vsrtpzmbkfge17tre96ky480w0lcsy7rwe.png)
The sum of all differences, using their absolute value, would be:
![5+10+10+15+25+5+10=80](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7lzommfaii46jafjbqzs4jtc6g3i0tb4h9.png)
Then, we divide this result by the total number of elements which is 7:
![(80)/(7) \approx 11.43](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f147hsjq0aa3y0j34er4e4h8evc9wnp1xy.png)
Therefore, the mean absolute deviation is approximately is 11.43.