Question

Describe the redox reaction. Check all that apply 2AI(s) + 3ZnCI2(g) → 3Zn(s) + 2AICI3(aq).

Aluminum atoms transfer electrons to chlorine atoms.

Zinc is reduced.

Zinc is the reducing agent.

The oxidation number of chlorine does not change.

Aluminum is oxidized.

Answer 1

Answer: B, D,E

Step-by-step explanation:

Answer 2

Zinc is reduced.

The oxidation number of chlorine does not change.

Aluminum is oxidized.

Step-by-step explanation:

• For the reaction:

2AI(s) + 3ZnCI₂(g) → 3Zn(s) + 2AICI₃(aq).

• For the elements in the reactants side:

Al has (0) oxidation state and converted to (+3) oxidation state in the products (AlCl₃), which means Al is oxidized and it is the reducing agent.

So, we can check that: Aluminum is oxidized.

Zn has the oxidation state (+2) in the reactants side (ZnCl₂) and converted to (0) in the products side (Zn), which means that Zn is reduced and it is the oxidizing agent.

So, we can check that: Zinc is reduced.

and can not check: Zinc is the reducing agent.

The oxidation state of Cl does not change, it is the same in both sides (-1).

So, we can check: The oxidation number of chlorine does not change.

and can not check: Aluminum atoms transfer electrons to chlorine atoms.

• So, the choices will be:

Zinc is reduced.

The oxidation number of chlorine does not change.

Aluminum is oxidized.