For this case we must factor the following expression:
![5y ^ 4 + 11y ^ 2 + 2](https://img.qammunity.org/2020/formulas/mathematics/college/3eu52cbn38uhbkac1j6yv9kglyq4g06l6u.png)
We rewrite
as
:
![5 (y ^ 2) ^ 2 + 11y ^ 2 + 2](https://img.qammunity.org/2020/formulas/mathematics/college/y6rqiga7octawq1b005k54zwr9eu9lfmkm.png)
We make a change of variable:
![u = y ^ 2](https://img.qammunity.org/2020/formulas/mathematics/college/7z57oe2jpea63j3c1vuwamzy48go0b63bg.png)
So, we have:
![5u ^ 2 + 11u + 2](https://img.qammunity.org/2020/formulas/mathematics/college/ksmo0n79qtqe4qwz13cj7f0e31vyrfv4gz.png)
we rewrite the term of the medium as a sum of two terms whose product is 5 * 2 = 10 and whose sum is 11. Then:
![5u ^ 2 + (1 + 10) u + 2\\5u ^ 2 + u + 10u + 2](https://img.qammunity.org/2020/formulas/mathematics/college/onqto7buu1lj17snxv1z6vmwof56dqzs5u.png)
We factor the highest common denominator of each group:
![u (5u + 1) +2 (5u + 1)](https://img.qammunity.org/2020/formulas/mathematics/college/1wp845bwbm2130i7n625vj60h5ed4y2ooi.png)
We factor
![(5u + 1):](https://img.qammunity.org/2020/formulas/mathematics/college/w051glchr01alhnop2sspfronjk2oaswss.png)
![(5u + 1) (u + 2)](https://img.qammunity.org/2020/formulas/mathematics/college/ra9vtoclfzpj2sw1mreys59mwigjwvplpy.png)
Returning the change:
![(5y ^ 2 + 1) (y ^ 2 + 2)](https://img.qammunity.org/2020/formulas/mathematics/college/aoxvbo1eksgc7vxwx8jvn1cjwy6s1zteu6.png)
ANswer:
![(5y ^ 2 + 1) (y ^ 2 + 2)](https://img.qammunity.org/2020/formulas/mathematics/college/aoxvbo1eksgc7vxwx8jvn1cjwy6s1zteu6.png)