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Julie has 5 cherry lollipops,1 lime lollipops, and 2 grape lollipops in a bag. She is going to select one lollipop, replace the lollipop in the bag, and then select a second one. What is the probability that Julie will select a cherry lollipop and then a lollipop other than grape?

a.)6/8

b.)11/16

c.)15/32

d.)10/64

1 Answer

4 votes

Answer:
(15)/(32)

Explanation:

Given : The number of cherry lollipop = 5

The total number of lollipop = 8

the number of lollipops other than grape =6

The probability of selecting a cherry lollipop is given by :_


\text{P(Cherry)}=(5)/(8)

The probability of selecting a lollipop other than grape is given by :_


\text{P(Other than grape)}=(6)/(8)

Since, there is replacement , then the events are independent of each other.

Now, the probability that Julie will select a cherry lollipop and then a lollipop other than grape is given by :-


\text{P(Cherry and other than grape)}=(5)/(8)*(6)/(8)=(15)/(32)

Hence, the required probability =
(15)/(32)

User Chris Roberts
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