Answer:
0.042 m^3
Step-by-step explanation:
side, a = 0.5 m, m = 100 kg
density of fluid, d = 1.2 g/cm^3 = 1200 kg/m^3
Volume of cube, V = side^3 = (0.5)^3 = 0.125 m^3
density of solid = mass of solid / volume of solid cube
density of solid, D = 100 / 0.125 = 800 kg/m^3
Let v be the volume of cube immersed in fluid.
According to the principle of flotation
Weight of cube = Buoyant force acting on the cube
V x D x g = v x d x g
0.125 x 800 = v x 1200
v = 0.083 m^3
Volume above the level of fluid = V - v = 0.125 - 0.083 = 0.042 m^3