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Given the two reactions H2S⇌HS−+H+, K1 = 9.58×10−8, and HS−⇌S2−+H+, K2 = 1.58×10−19, what is the equilibrium constant Kfinal for the following reaction? S2−+2H+⇌H2S Enter your answer numerically.

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Answer:

K(net) = K₁ x K₂ = 1.51 x 10⁻²⁶

Step-by-step explanation:

Given the two reactions H2S⇌HS−+H+, K1 = 9.58×10−8, and HS−⇌S2−+H+, K2 = 1.58×10−19, what-example-1
User Robert Schillinger
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