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To estimate μ, the mean salary of full professors at American colleges and universities, you obtain the salaries of a random sample of 81 full professors. The sample mean is = $77,220 and the sample standard deviation is s = $4500. A 98% confidence interval for μ is _____.

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Answer with explanation:

Sample mean of 81 full Professor = $ 77,220

Sample Standard Deviation (S)= $ 4500

Sample mean= $77,220


Z_{98 \text{Percent}=(98)/(100)}\\\\Z_{98 \text{Percent}=0.8365}\\\\Z_{\text Score=(\bar x -\mu)/(\sigma)}\\\\0.84=(77220- \mu)/(4500)\\\\\mu=77220-3780\\\\ \mu=73440

So, When , z=98% , then Mean Salary ( μ)=73,440

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