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A conductor is formed into a loop that encloses an area of 1m^2. The loop is oriented at a angle 30 degree with the xy plane. A varying magnetic field is oriented parallel to the z axis. If the maximum emf induced in the loop is 10v, what is the maximum rate at which the magnetic field strength is changing?

User BudiDino
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1 Answer

2 votes

Answer:


(dB)/(dt) = 11.55 T/s

Step-by-step explanation:

As we know that flux of magnetic field from the closed loop is given by


\phi = BAcos30[tex]</p><p>now by Faraday's law we know</p><p>[tex]EMF = (d\phi)/(dt)

now we will have


EMF = Acos30(dB)/(dt)

now we have


A = 1 m^2

EMF = 10 Volts


10 = 1 (cos30)(dB)/(dt)


(dB)/(dt) = (20)/(\sqrt3)


(dB)/(dt) = 11.55 T/s

User Sivabalan
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