Question

A conductor is formed into a loop that encloses an area of 1m^2. The loop is oriented at a angle 30 degree with the xy plane. A varying magnetic field is oriented parallel to the z axis. If the maximum emf induced in the loop is 10v, what is the maximum rate at which the magnetic field strength is changing?

Answer 1

`(dB)/(dt) = 11.55 T/s`

Step-by-step explanation:

As we know that flux of magnetic field from the closed loop is given by

`\phi = BAcos30[tex]</p><p>now by Faraday's law we know</p><p>[tex]EMF = (d\phi)/(dt)`

now we will have

`EMF = Acos30(dB)/(dt)`

now we have

`A = 1 m^2`

EMF = 10 Volts

`10 = 1 (cos30)(dB)/(dt)`

`(dB)/(dt) = (20)/(\sqrt3)`

`(dB)/(dt) = 11.55 T/s`