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Calculating work for different springs Calculate the work required to stretch the following springs 0.5 m from their equilibrium positions. Assume Hooke’s law is obeyed. a. A spring that requires a force of 50 N to be stretched 0.2 m from its equilibrium position. b. A spring that requires 50 J of work to be stretched 0.2 m from its equilibrium position.

1 Answer

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Answer:

Part a)

U = 31.25 J

Part b)

U = 312.5 J

Step-by-step explanation:

Part A)

A spring that requires a force of 50 N to be stretched 0.2 m from its equilibrium position.

So here we have


F = kx


50 = k(0.2)

k = 250 N/m

now the energy stored in the spring is given by


U = (1)/(2)kx^2


U = (1)/(2)(250)(0.5)^2


U = 31.25 J

Part B)

A spring that requires 50 J of work to be stretched 0.2 m from its equilibrium position.

So here we know the formula of spring energy as


U = (1)/(2)kx^2


50 = (1)/(2)k(0.2)^2


k = 2500 N/m

now by the formula of energy stored in spring


U = (1)/(2)kx^2


U = (1)/(2)(2500)(0.5)^2


U = 312.5 J

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