Question

Write the equation of the circle passing through the origin with center (– 9, –12) .

(x + 9) – (y −12) = 325

(x + 9)2 + (y +12)2 = 225

(x + 9)2 + (y +12)2 = 325

(x − 9)2 + (y −12)2 = 225

(x − 9)2 + (y −12)2 = 325

Answer 1

`(x+9)^(2) +(y+12)^(2)=225`

Explanation:

Remember that the center of a circle is written in (h,k) format. So h= - 9 and k = -12. Also, the distance between those two points is 15 units, so r = 15.

So the formula
`(x-h)^(2) +(y-k)^(2)=r^(2)`

Should look like
`(x+9)^(2) +(y+12)^(2)=225`