Question

The value of k so that the sequence k-1, k+3, 3k-1 forms an arithmetic progression is?​

Answer 1

k = 4.

Explanation:

An arithmetic sequence has a common difference.

So for this to be arithmetic:

k + 3 - (k - 1) = 3k - 1 - (k + 3)

k + 3 - k + 1 = 3k - 1 - k - 3

3 + 1 = 2k - 4

4 + 4 = 2k

k = 4.

The sequence is 3, 7, 11.