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From a survey taken several years ago, the starting salaries of individuals with an undergraduate degree from Business Schools are normally distributed with a mean of $40,500 and a standard deviation of $4,500.What is the probability that a randomly selected individual with an undergraduate business degree will get a starting salary of at least $36,000.00? (Round your answer to 4 decimal places.)

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Answer: 0.8413

Explanation:

Given: Mean :
\mu=\$40,500

Standard deviation :
\sigma = \$4,500

The formula to calculate z-score is given by :_


z=(x-\mu)/(\sigma)

For x= $36,000.00, we have


z=(36000-40500)/(4500)=-1

The P-value =
P(z\geq-1)=1-P(z<-1)=1-0.1586553=0.8413447\approx0.8413

Hence, the probability that a randomly selected individual with an undergraduate business degree will get a starting salary of at least $36,000.00 = 0.8413

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