Question

Please help me!!!!!!!!

Answer 1

A. (2, 1)

Explanation:

`\left\{\begin{array}{ccc}3x+4y=10&(1)\\y=x-1&(2)\end{array}\right\\\\\text{Substitute (2) to (1):}\\\\3x+4(x-1)=10\qquad\text{use the distributive property}\\3x+4x-4=10\qquad\text{add 4 to both sides}\\7x=14\qquad\text{divide both sides by 7}\\x=2\\\\\text{put the value of x to (2):}\\\\y=2-1\\y=1`

Answer 2

(2,1)

Explanation:

So the first thing you want to do is substitute. You want to plug in the equation for y in for the y value above.

So you would do 3x+4(x-1)=10. As you can see we took the bottom equation and put it in for the top equation. We did this so we only have x s and no y s.

Now you would solve. You would distribute first. You would get 3x+4x-4=10. Now combine like terms. 3+4 is 7 so you would get 7x-4=10.The next thing you want to do is get the 7x by itself so move the 4.You would get 7x=14. Now divided both sides by 7 because you want to get the x by itself.

You would get x=2. Now for the y value just plug it in for an equation above. The easier one would be y=x-1. y=(2)-1 will equal 1. You write your final answer in (x,y) style. Your final answer will then be (2,1)