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The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the smaller angle

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Complementary angles are pair of two non-right angles whose sum is equal to 90°

Let the two complementary angles be : Δ and Ф

Given : Sum of the measures of two complementary angles exceed the difference of their measures by 72°


:\implies Δ + Ф - 72° = Δ - Ф


:\implies 2Ф = 72°


:\implies Ф = 36°

As Δ and Ф are complementary, their sum should be equal to 90°


:\implies Δ + 36° = 90°


:\implies Δ = 90° - 36°


:\implies Δ = 54°

So, Complementary angles are 54° and 36°

Answer : The Measure of the Smaller Angle is 36°

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