141k views
3 votes
Writing a quadratic equation given the roots and the leading coefficient

roots 6, 4, and coefficient 5

User Alafia
by
7.6k points

1 Answer

5 votes


\bf x= \begin{cases} 6\\ 4 \end{cases}\implies \begin{cases} x=6\implies &x-6=0\\ x=4\implies &x-4=0 \end{cases} \\\\\\ (x-6)(x-4)=\stackrel{y}{0}\implies \stackrel{\mathbb{F~O~I~L}}{x^2-10x+24}=0\implies \stackrel{\textit{adding a common factor of 5}}{5(x^2-10x+24)=0} \\\\\\ 5x^2-50x+120=0\implies 5x^2-50x+120=y

now, the common factor of 5 simply makes the parabola steeper, but the roots are the same, whilst the vertex of it changes

User Oded Breiner
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories