Answer:
41.4 m/s
Step-by-step explanation:
Consider downward direction of motion as negative
v₀ = initial velocity of the package as it is dropped over the side = 12 m/s
v = final velocity of the package just before it hits the ground
y = vertical displacement of the package = - 80 m
a = acceleration = - 9.8 m/s²
Using the kinematics equation
v² = v₀² + 2 a y
v² = 12² + 2 (- 9.8) (- 80)
v² = 144 + 1568
v = - 41.4 m/s
The negative sign indicates the downward direction of motion.
Hence the speed of package comes out to be 41.4 m/s