Question

Calculate the magnitude of the force between two point charges where q1 = +5.30 ?C and Q2 = +11.2 11C where the separation between the charges is R = 0.22 m. O A. 11.0 Newtons O B. 18.3 Newtons ° C. 27.4 Newtons 0 D. 41.5 Newtons

Answer 1

Magnitude of force, F = 11 Newtons

Step-by-step explanation:

Charge 1,
`q_1=5.3\ \mu C=5.3* 10^(-6)\ C`

Charge 2,
`q_2=11.2\ \mu C=11.2* 10^(-6)\ C`

The separation between the charges is, r = 0.22 m

We have to find the magnitude of the force between two point charges. It can be calculated using the formula as :

`F=k(q_1q_2)/(r^2)`

`F=9* 10^9* (5.3* 10^(-6)\ C* 11.2* 10^(-6)\ C)/((0.22\ m)^2)`

F = 11.03 N

or

F = 11 Newtons

Hence, this is the required solution.