Question

A 1.7cm diameter pipe widens to 4.7cm. Liquid flows through the first segment at a speed of 4.7m/s. What is the speed of the liquid in the second segment?

Answer 1

Speed of the liquid in the second segment = 0.61 m/s

Step-by-step explanation:

This discharge is constant.

That is

Q₁ = Q₂

A₁v₁ = A₂v₂

`(\pi d_1^2)/(4)* v_1=(\pi d_2^2)/(4)* v_2\\\\(\pi * 1.7^2)/(4)* 4.7=(\pi * 4.7^2)/(4)* v_2\\\\v_2=0.61m/s`

Speed of the liquid in the second segment = 0.61 m/s