Answer:
Electrical energy consumed, E = 1.95 × 10⁻⁵ kWh
Step-by-step explanation:
It is given that,
Power rating on the light bulb, P = 75 W
We need to find the electrical energy consumed by the bulb in 1 second of time i.e in 0.00026 hours.
![P=(energy\ consumed)/(time)](https://img.qammunity.org/2020/formulas/physics/college/e4g9uphkqj7bfitwoipk7lp0hafpwi6jky.png)
Energy consumed, E = P × t
E = 75 W × 0.00026 h
E = 0.0195 W-h
Energy consumed is calculated in kilo watt hour. Since, 1 watt = 0.001 kW
So, E = 1.95 × 10⁻⁵ kWh
Hence, this is the required solution.