Question

What are the solutions of x^2+12x+32=0 use the quadratic formula

Answer 1

Quadratic formula:

`$x=(-b\pm√(b^2-4ac))/(2a)$`

Input the corresponding numbers:

`$x=(-12\pm√(12^2-4(1)(32)))/(2(1))$`

Solve:

`x=(-12+√(12^2-4(1)(32)))/(2(1))\\ x = -4\\ \\ x=(-12-√(12^2-4(1)(32)))/(2(1))\\ x=-8`

So, the solutions are x = -4 and x = -8