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A ball is thrown with a velocity of 3.0 m/s at an angle of 30° above horizontal. Its vertical velocity is zero when: The ball is at its maximum height. Just before the ball hits the ground. When the ball changes direction. Never during the ball's flight.

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Answer:

The ball is at its maximum height.

Step-by-step explanation:

As we know that when ball is thrown at some angle with the horizontal then the component of its velocity is given as


v_x = vcos\theta


v_y = vsin\theta

now here vertical velocity is the velocity in y direction

so it is given as


v_y = 3.0 sin30 = 1.5 m/s

now as the velocity of ball in vertical direction becomes zero

then in that case


v_f - v_i = at


0 - 1.5 = (-9.8)t


t = 0.15 s

since at this position the vertical component of the velocity is zero

so this is the position of ball when its height is maximum

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