Question

F(n+1)=f(n)-8. If f(2)=100, what is f(6)

Answer 1

`f(n+1)=f(n)-8\\f(2)=100\\\\f(3)=100-8=92\\f(4)=92-8=84\\f(5)=84-8=76\\f(6)=76-8=68`

Answer 2

f(6) = 68

Explanation:

f(6)

f(n+1)=f(n)-8

n = 5, so

f(6)=f(5)-8

and with n = 4

f(5)=f(4)-8 , so

f(4) = f(3) - 8

f(3) = f(2) - 8 = 100 - 8 = 92

f(3) = 92

Then, we can go and find the result

f(4) =[92] - 8 = 84

f(5)=[84] - 8 = 76

f(6) = [76] -8 = 68