Answer:
Resistance of the bulb is 2100 watts.
Step-by-step explanation:
Given that,
Power of the bulb, P = 7.5 watts
Voltage, V = 125 volts
We have to find the resistance of the bulb. The power of an electrical appliance is given by the following formula as :
![P=(V^2)/(R)](https://img.qammunity.org/2020/formulas/physics/college/c0948fndyx81ji5a2scaeg6ikt2aiips8c.png)
![R=(V^2)/(P)](https://img.qammunity.org/2020/formulas/physics/college/y2pw9cqdrmbeo9javsvhs4mkzg71wmhbgk.png)
![R=((125\ V)^2)/(7.5\ W)](https://img.qammunity.org/2020/formulas/physics/college/pevf40cj4ldk9ejgc8io12aguqtm3q23br.png)
R = 2083.34 ohms
or
R = 2100 ohms
Hence, the correct option is (d) "2100 ohms"