Question

What is the maximum speed with which a 1200-kg car can round a turn of radus 84.0 m on a flat road if the coefficient of static friction between tires and road is 0.60. Express your answer to two significant figures and include the apprepriate units.

Answer 1

Step-by-step explanation:

It is given that,

Mass of the car, m = 1200 kg

Radius of circular path, r = 84 m

The coefficient of static friction between tires and road is 0.60

Static friction is given by :

`f=\mu N=\mu mg`..............(1)

When an object is moving in a circular path, the centripetal force will act on it. It is given by :

`F=(mv^2)/(r)`

Let v is the maximum speed of the car. From equation (1) and (2) as :

`v=√(\mu gr)`

g = acceleration due to gravity

`v=√(0.6* 9.8\ m/s^2* 84\ m)`

v = 22.22 m/s

or

v = 22 m/s

Hence, this is the required solution.