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Which expression gives the distance between the points (4,6) and (7,-3)

User Tuffwer
by
8.3k points

2 Answers

4 votes

Answer:

D = 9.4868

Explanation:

The expression is the following

D = √((x2-x1)^2+(y2-y1)^2)

Where

(x1,y1) = (4,6)

(x2,y2) = (7,-3)

D = √((7-4)^2+(-3-6)^2)

D = √((3)^2+(-9)^2)

D = √(9+81)

D = √(90)

D = 9.4868

User Zsolt Bendes
by
8.0k points
2 votes

Answer:


d = \sqrt{(7-4)^(2)+(-3-6)^(2)}

Explanation:

The expression used for calculating distance between two points involves the square root of sum of squares of differences of x-intercepts and y-intercepts.

The formula is given by:


d = \sqrt{(x_(2) -x_(1) )^(2)+(y_(2)- y_(1) )^(2) }

Here,


(x_(1),y_(1)) = (4,6)\\ (x_(2),y_(2)) = (7,-3)\\Putting\ the\ values\\d = \sqrt{(7-4)^(2)+(-3-6)^(2)}

Hence, the following expression will give the distance between given points


d = \sqrt{(7-4)^(2)+(-3-6)^(2)}

Solving it will give:


d = \sqrt{(3)^(2)+(-9)^(2)}\\= √(9+81)\\=√(90)

User Tringuyen
by
7.6k points

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