Question

A 222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left Find the total momentum of the system.

Answer 1

Total momentum of the system is 378 kg-m/s

Step-by-step explanation:

It is given that,

Mass of first bumper car, m₁ = 222 kg

Velocity of first bumper car, v₁ = 3.10 m/s (in right)

Mass of other bumper car, m₂ = 165 kg

Velocity of second bumper car, v₂ = -1.88 m/s (in left)

Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :

`p=m_1v_1+m_2v_2`

`p=222\ kg* 3.10\ m/s+165\ kg* (-1.88\ m/s)`

p = 378 kg-m/s

Hence, the total momentum of the system is 378 kg-m/s