Answer:
y = mx + 5; m < 0
Explanation:
The question mentions that the slope of the line is negative and the y-intercept is 5. The general form of the straight line is given by y = mx + c. Since "c" in the equation is the y-intercept, therefore, c = 5. This means that all the straight lines passing from the point (0,5) can be expressed in a general form y = mx + 5. However, the question mentions that the slope is negative and demands the general equation of all the negatively-sloped straight lines passing from (0,5). Therefore, for the condition to be met, m has to be negative. So the correct answer is y = mx + 5, where m is negative.