Question

How do you calculate the boiling point of pure water at 653.7 torr?

Answer 1

Step-by-step explanation:

It is known that atmospheric pressure is equal to 760 torr.

And, at atmospheric pressure that is, 760 torr the boiling point of pure water is 100 degree celsius.

So, calculate the boiling point of pure water at 653.7 torr as follows.

`(100^(o)C)/(760 torr) * 653.7 torr`

=
`0.131 * 653.7 torr`

=
`86.01^(o)C`

Therefore, we can conclude that the boiling point of pure water at 653.7 torr is
`86.01^(o)C`.