Question

Find b. given that a = 20, angle A= 30°, and angle B = 45° in triangle ABC.

a = 20
300
45
10_2
20/2
20/3
4022

Answer 1

The value of b is 28.28

Explanation:

We would use Law of sines to find the value of b

The law of sines is:

`(a)/(sinA)=(b)/(sinB)`

We are given

a= 20

A = 30°

B = 45°

b=?

Putting values in the formula:

`(20)/(sin(30))=(b)/(sin(45))\\(20)/(0.5)=(b)/(0.707)\\b = (20)/(0.5) * 0.707\\b = 40 * 0.707\\b= 28.28\\`

The value of b is 28.28